# An Introduction to Mensuration and Practical Geometry

U. Hunt & son, 1833 - 288 ページ

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50 ページ - The areas of circles are to each other as the squares of their diameters.
217 ページ - Also, as a cubic foot of water weighs just 1000 ounces avoirdupois5 the numbers in the table express, not only the specific gravities of the several bodies, but also the weight of a cubic foot of each in avoirdupois ounces ; and...
20 ページ - In a right-angled triangle, the side opposite to the right angle, is called the hypothenuse ; and the other two sides are called the legs, and sometimes the base and perpendicular : thus, A, B is the base, B, C perpendicular, and A, C hypothenuse.
125 ページ - To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity.
192 ページ - ... foot ; there being three stories, and three windows in each story. The height of the lower tier is 7 feet 9 inches, of the middle 6 6 of the upper 5 3| and of an oval window over the door 1 105 the common breadth of all the windows being 3 feet 9 inches. Ans. £12, Is. 8|d. PAVERS' WORK — Pavers- work is done by the square yard.
21 ページ - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
260 ページ - MECHANICAL POWERS are certain simple instruments employed in raising greater weights, or overcoming greater resistance than could be effected by the direct application of natural strength. They are usually accounted six in number; viz. the Lever, the Wheel and Axle, the Pulley, the Inclined Plane, the Wedge, and the Screw.
96 ページ - As the conjugate diameter is to the transverse, So is the square root of the difference of the squares of the ordinate and semi-conjugate, To the distance between the ordinate and centre.
15 ページ - The radius of a circle is a right line drawn from the centre to the circumference.
54 ページ - To find the Area of a Triangle. Rule ] . Multiply the base by the perpendicular height, and half the product will be the area.