 | Robert Simson - 1762 - 488 ページ
...equal . therefore ^ remainder AL is equal to the remainder f BG. but it has been fhewn that BC is equal to BG ; wherefore AL and BC are each of them equal...ftraight line AL is equal to BC. Wherefore from the given pojnt A a ftraight line AL has been drawn equal to the given ftraight line BC. Which was to be done.... | |
 | Robert Simson - 1775 - 534 ページ
...therefore the remainder AL is equal to the remainder f BG i But it has been fhewn, that BC is equal to BG ; wherefore AL and BC are each of them equal...the given ftraight line BC. Which was to be done. PROP. III. PRO B. .OM the greater of two given ftraight lines to cut off a part equal to the lefs.... | |
 | Robert Simson - 1781 - 534 ページ
...f. 3. Ax. the remainder AL is equal to the remainder f BG. but it has been fiiewn that BC is equal to BG ; wherefore AL and BC are each of them equal...is equal to BC. Wherefore from the given point A a ftraightline ALhas been drawn equal to the given ftraight line BC. Which was to be done. F PROP. III.... | |
 | Euclid - 1781 - 552 ページ
...remainder AL is equal to the remainder f I But it has been fhewn, that BC is equal to BG ; wherefore and BC are each of them equal to BG ; and things that equal to the fame are equal to one another ; therefore ftraight line AL is equal to BC. Wherefore from... | |
 | Alexander Ingram - 1799 - 374 ページ
...been Ihewn, that BC is equal to BG ; wherefore AT, and BC are epch of them equal to BG ; and tiiings that are equal to the fame, are equal to one another...point A a ftraight line AL has been drawn equal to the givea ftraight line BC. Which was to be done. PROP. III. PROB. <ROM the greater of two given ftraight... | |
 | Robert Simson - 1804 - 530 ページ
...therefore 3. Ax, the remainder AL is equal to the remainder f BG. but it has been fhewn that BC is equal to BG ; wherefore AL and BC are each of them equal...the given ftraight line BC. Which was to be done. PROP. III. PRO B. 'ROM the greater of. two given ftraight lines to «ut off a part equal to the lefs.... | |
 | Daniel Merrill - 1805 - 354 ページ
...covenant betwixt God and Abraham equal, the covenant of ctrcumcifion : for it is a well known axiom, that things that are equal to the fame are equal to one another.' This algebraic equation, my friead, in pity to you, t will. leave under a fimple quotation." Some of... | |
 | Robert Simson - 1806 - 546 ページ
...therefore the remainder AL is equal to the remainder f BG : but it has been shown, that BC is equal to BG ; wherefore AL and BC are each of them equal to BG ; and things that are equal to the same ave equal to one another ; therefore the straight line AL is equal to BC. Wherefore from the given... | |
 | Euclid - 1810 - 554 ページ
...therefore the remainder AL is equal to the remainder f BG: but it has been shown, that BC is equal to BG; wherefore AL and BC are each of them equal to BG; and thinge that are equal to the same are equal to one another; therefore the straight lme AL is equal... | |
 | Euclides - 1814 - 560 ページ
...shown, that BC is them, are equal; therefore the remainder AL is equal to equal to BG; wherefore'AL and BC are each of them equal to BG; and things that are equal to the same are equal to one another; therefore the straight line AL is equal to BC. Wherefore from the given... | |
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Wherefore, from the given point A, a straight line AL has been drawn equal to the given straight line BC. 
