 | 1867 - 964 ページ
...any point in tho straight line HK, produced both ways indefinitely. Triangles also which stand npon equal bases and between the same parallels are equal to one another. Thus, the triangles LNG, M o F, which „ ._ stand on equal bases, NG, F o, and K between the same... | |
 | Robert Gibson - 1806 - 486 ページ
...parallelogram are equal ; for it has been proved that ABCD being a parallelogram, AB will be=CD and AD = BC, THEOREM XIII, All parallelograms on the same or equal...BD^GH, and the lines BH and AF parallel, then the parallel0gram ABDC ^BDFE=EFHG. .fig. 31. For AC=BD=EF (by cor. the last ;) to both add CE then AE=CF.... | |
 | John Playfair - 1806 - 320 ページ
...EBCF. Therefore, parallelograms upon the same base, &c. QED PROP. XXXVI. THEOR. PARALLELOGRAMS upon equal bases, and between the same parallels, are equal to one another. Let ABCD, EFGH be parallelograms upon equal bases BC, FG, and between the same parallels AH, BG; the... | |
 | Robert Simson - 1806 - 546 ページ
...is'equal to the triangle DBC. Wherefore, triangles, fee, QE D, PROP. XXXVIII. THEOR. TRIANGLES upon equal bases, and between the same parallels, are equal to one another. Let the triangles ABC, DEF be upon equal bases BC, EF, and between the same parallels BF, AD : the... | |
 | Robert Gibson - 1808 - 482 ページ
...the parallelogram EFGH=BDEF. Wherefore ABDC=BDEF=EFHG. QED " Cor. Hence it is plain that triangles on the same or equal bases and between the same parallels, are equal, seeing (by cor. 2. theo. 12.) they are the halves of their respective parallelograms. THEO. XIV. In... | |
 | Robert Gibson - 1811 - 580 ページ
...|»rallelogram E FG H= B DEF. Wherefore ABDC=> BDEF=EFHG. 3. ED Cor. Hence it is plain that triangles on the same or equal bases, and between the same parallels, are equal, seoing (by cor. 2. theo. 1Q.) theyavf the halves of their respective parallelogram • THEO. XIV. PL.... | |
 | John Mason Good - 1813 - 714 ページ
...base, and between the same parallels, are equal to one another. Prop. XXXVIII. Theor. Triangles upon equal bases, and between the same parallels, are equal to one another. Prop. XXXIX. Theor. Equal triangles upon the same base, and upon the same side of it, are between the... | |
 | Robert Gibson - 1814 - 558 ページ
...the parallelogram EFGH=BDEF. Wherefore ABDC=BDEF=EFHG. QED ч Cor. Hence it is plain that triangles on the same or equal bases, and between the same parallels, are equal, seeing (by cor. 2. theo. 12.) they are the halves of their respective parallelogram. THEO. XIV. PL.... | |
 | Euclides - 1816 - 588 ページ
...Therefore parallelograms upon the same base, &c. QED 1 PROP. XXXVI. THEOR. Boot I. PARALLELOGRAMS upon equal bases, and between the same parallels, are equal to one another. •f> K LetABCD,EFGH,be parallelograms upon equal bases BC,FG, and between the same parallels AH, BG;... | |
 | John Playfair - 1819 - 354 ページ
...Therefore, parallelograms upon the same base, &c. Q. E%13. PROP. XXXVI. THEOR. Parallelograms upon equal bases, and between the same parallels, are equal to one another. Let ABCD, EFGH be parallelograms upon equal bases BC, FG, A DE and between the same parallels AH, BG... | |
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Triangles upon equal bases, and between the same parallels, are equal to one another. 
