 | 1829 - 906 ページ
...Weight in C 33600 x 13 » the middle. ? - 500 - =8™ ./873=9| inches diameter. X .3=436800 36800_ 6 10 To Resist Torsion or Twisting. It is obvious that...engine, at 50 revolutions per minute, requires to be 7k inches diameter, and, therefore, the cube of this diameter, which is = 421.875, serves as a multiplier... | |
 | William Templeton (engineer.) - 1833 - 224 ページ
...96 . 3V 512Q = 2£ inches nearly. In the case of revolving shafts for machinery, &c. the strength is directly as the cubes of their diameters and revolutions,...inversely as the resistance they have to overcome ; hence, From practice, we find that a 40.horse power steam engine, making 25 revolutions per minute,... | |
 | 1836 - 848 ページ
...twitting. It is obvious that the strength of revolving shafts are directly as the cubes of their diameter and revolutions ; and inversely as the resistance they have to overcome. Mr. Buchanan, in his Essay 011 the strong th of shafts, gives the following data, deduced from several... | |
 | 1847 - 190 ページ
...cubes of their diameters and revolutions; and inversely, as the resistance they have to overcomeMr Robertson Buchanan, in his essay on the Strength of...deduced from several experiments, viz- : That the fly-wheel shaft of a 50horse-power engine, at 50 revolutions per minute, requires to be 74 inches diameter... | |
 | Thomas Kelt - 1849 - 424 ページ
...diameter. Weight equally distributed, 33600 X 13 = 436800 = 7-65 inches. 10 To resist Torsion or Twi&ing. It is obvious that the strength of revolving shafts*...deduced from several experiments, viz. : That the fly-wheel shaft of a 50horse-power engine, at 50 revolutions per minute, requires to be 74 inches diameter... | |
 | J. M. Scribner - 1849 - 286 ページ
...velocity in feet, and the product by -002288, the result is the force in avoirdupois pounds. RESISTANCE TO TORSION OR TWISTING. It is obvious that the strength...inversely, as the resistance they have to overcome. Mr. Buchanan, in his Essay on the Strength of Shafts, gives the following data,- deduced from several experiments,... | |
 | Oliver Byrne - 1851 - 310 ページ
...563 2150 717 1206 402 1536 512 In the case of revolving shafts for machinery, &c., the strength is directly as the cubes of their diameters, and revolutions,...inversely as the resistance they have to overcome ; hence, From practice, we find that a 40 horse power steam engine* making 25 revolutions per minute,... | |
 | Charles Haslett - 1855 - 544 ページ
...-65 inches. '" Tu realst Torsion or Twisting. It is obvious that the strength of revolving shafts* is directly as the cubes of their diameters, and revolutions;...Buchanan, in his Essay on the Strength of Shafts, gives tile following data, deduced from several experiments, viz. : That the fly-wheel shaft of a 50-horse-... | |
 | Charles W. Hackley - 1856 - 530 ページ
...It is obvious that; the strength of revolving shafts* is directly as the cubes of their jdiameters and revolutions • :and -inversely as the resistance they have to overcome. Mr. Robertson ;Bnchan an, in his Essay on • the Strength of Shafts, gives the following data, deduced from several:... | |
 | 1855 - 420 ページ
...3^/813 = 9A inches 500 diameter. Weight equally distributed, 33600 X 13 = 436800 = 7-65 inches. 10 To resist Torsion or Twisting. It is obvious that...data, deduced from several experiments, viz.: That the fly-wheel shaft of a 50horse-power engine, at 50 revolutions per minute, requires to be 7J inches diameter... | |
| |
It is obvious that the strength of revolving shafts* are directly as the cubes of their diameters and revolutions; and inversely, as the resistance they have to overcome. Mr. Robertson Buchanan, in his essay on the Strength of Shafts, gives the following... 