 Divide the number 90 into 4 such parts, that the . first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal.  A Drill-book in Algebra - 81 ページGeorge William Jones 著 - 1892 - 272 ページ全文表示 - この書籍について
 | 1801 - 446 ページ
...but I2S. remaining ; what had he at first ? Ans. 2os. 21. To divide the number 90 into 4 such parts, that if the first be increased by 2, the second diminished...the third multiplied by 2, and the fourth divided by 2t" the sum, difference, product, and quotient, shall be all equal to each other. Ans. The parts are... | |
 | Bewick Bridge - 1818 - 254 ページ
...inverted. What is the number ? ANSW. 53. Qu. 33. Divide the number 90 into four such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, may all be equal to the same quantity. ANSW. 18, 22, 10, 40. Qu. 34. A merchant has two kinds often,... | |
 | Bewick Bridge - 1821 - 648 ページ
...inverted. What is the number ? ANSW. 53. Qu. 33. Divide the number 90 into four such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, may all be equal to the same quantity. ANSW. 18,22,10,40. Qu. 34. A merchant has two kinds of tea,... | |
 | Jeremiah Day - 1827 - 352 ページ
...each horse ? Ans. 56 and 33 guineas. Prob. 30. Divide the number 90 into 4 such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. If x, y, and z, be three of the parts, the fourth will be 90 — x—y — z. And... | |
 | John Bonnycastle - 1829 - 372 ページ
...? Ans. 300. J2. It is required to divide the number 90 into four such parts, that if the first part be increased by 2, the second diminished by 2, the third multiplied by i?, and tht fourth divided by 2, the sum, difference, product, and quotient, shall be all equal ? Ans.... | |
 | Frederick Augustus Porter Barnard - 1830 - 304 ページ
...A. A's 84, B's 42, C's 14. 34. Divide the number 90 into 4 such parts, that the first, in. . creased by 2, the second, diminished by 2, the third, multiplied by 2, and the fourth, divided by 2, shall all be equal. A. 18 ; 22 ; 10 ; and 40. 35. A person at play lost } of his money, and then won... | |
 | John Bayley (fellow of Emmanuel College, Cambridge.) - 1830 - 428 ページ
...a*-i-(x — a) = x + a . • . x+a = b . • . x = b — a. Divide the number 90 into four such parts, that if the first be increased by 2, the second diminished by two, the third multiplied by 2, and the fourth divided by 2, the result in each case will be the same.... | |
 | Jeremiah Day - 1831 - 358 ページ
...each horse ? Ans. 56 and 33 guineas. Prob. 30. Divide the number 90 into 4 such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall all be equal. If x, y, and z, be three of the parts, the fourth will be 90 r- x - y - z. And... | |
 | Bewick Bridge - 1839 - 280 ページ
...QUADRATIC EQUATIONS. ' Tf » '.* Qu. 33. Divide the number 90 into four such parts, that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, may all be equal to the same quantity. ,,- v : - ., ANSW. 18, 22, 10, 40. ~ft iJ C' s- / f *ff ^ /... | |
 | Charles Davies - 1839 - 272 ページ
...y and z. • o 4 O a;=12, y=20, ^ = 30. 4. Divide the number 90 into four such parts that the first increased by 2, the second diminished by 2, the third multiplied by 2, and the fourth divided by 2, shall be equal to each other. This question may be easily solved by introducing a new unknown quantity.... | |
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