 | Robert Gibson - 1795 - 384 ページ
...the Squares of the Bafe and Perpendicular, will be the Hypothenufe. Cor. 2. Having .the Hypothenufe and one Leg given to find the other ; the Square Root of the Difference of the Squares of the Hypothenufe and given Leg, will be the required Leg. r HE o. xv. In all Circles the Chord of 60 Degrees... | |
 | Robert Gibson - 1808 - 482 ページ
...AC+BC : : AC— BC : AD— DB. 2.5 4.3 .3 .516. 1>25+.258=1.50S=AD. By cftr. 2. theo. 14. sett. 1. The square root of the difference of the squares of the hypothenuse AC, and given leg AD, will give DC. i. e* 5.29—2.274064=3.015936. Its square root is 1.736=CD. Then... | |
 | Robert Gibson - 1811 - 580 ページ
...of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the other ; the square root of the difference of the squares of the hypothenuse and given side, will be the required side. THEO. XV . PL. \.fig. 33. />; all circle* the chord of 60 dt'grtct... | |
 | Robert Gibson - 1814 - 558 ページ
...required. By Calculation. 1. AB : AC+BC- - AC—BC: AD—DB. 2.5 4.3 .3 .516. By cor. 2. theo. 14. geom. The square root of the difference of the- squares of the hypothenuse AC, and given leg AD, will give DC. That is, 5.29—2.274064=3.015936. « Its square root is 1.736=... | |
 | John Bonnycastle - 1818 - 488 ページ
...square root of the sum of the squares of the other two sides ; and either of the sides is equal to the square root of the difference of the squares of the hypothenuse and the other side. Note, also, that if the half difference of any two quantities be added to their half... | |
 | Robert Gibson - 1818 - 502 ページ
...i. AB : AC+BC : : AC— BC : AD— DB,=5l6, Then, 1.25+.258=1.508=AD. By cor. 2. theo. 14. sect. 1. The square root of the difference of the squares of the hypothenuse AC, and .given leg AD, will give DC,=1.736. Then, by the preceding lemma. 2. As CD : AC : : CB : the... | |
 | Robert Gibson - 1821 - 594 ページ
...squares of the base andperpendiculariwillbe the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the other ; the square root of the difference of the squares ofthe hypothenuse and given side, will be the required side. * For different demonstrations of this... | |
 | L. Murray - 1821 - 620 ページ
...scaling-ladder. 25 (0) Case 2. If the length of the base, or breadth of the ditch, were required ; then the square root of the difference of" the squares of the hypothenuse and perpendicular is the length of the base, or breadth of the ditch or moat. See the work. 2500 the square... | |
 | James Hale - 1829 - 124 ページ
...Squares, of the Base and Perpendicular, will be the Hypothenuse. — Having the Hypothenuse, and one Side, given to find the other ; The Square Root, of the difference of the Squares, of the Hypothenuse and the given Side, will be the required Side. REMARK IV. Triangles, having the same height, and standing... | |
 | Michael Walsh - 1831 - 348 ページ
...top of the wall. Ans. 39,05 feet. The hypolhenuse and perpendicular given, to find the base. RULE. The square root of the difference of the squares of the hypothenuse and perpendicular is the length of the base. The base and hypothenuse given, to find the perpendicular.... | |
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The hypothenuse of a right-angled triangle may be found by having the other two sides ; thus, the square root of the sum of the squares of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the... 
