 | Edward Augustus Kendall - 1811 - 462 ページ
...number of the sides of these is greater : the circle being always limited between the "two polygons. 3. The area of a circle is equal to that of a triangle...the circumference, and perpendicular equal to the radins. And therefore the area of the circle is found by multiplying half the circumference into half... | |
 | Edward Augustus Kendall - 1811 - 962 ページ
...circle being always limited between the two polygons. ," -8. The area of a circle is equal to that of ;i triangle whose base is equal to the circumference, and perpendicular equal to the radius. And there* fore the area of the circle is found by multiplying; half the circumference into half the... | |
 | Dugald Stewart - 1814 - 560 ページ
...may be expressed by the formula a = a ? Or, to take a case yet stronger, when it is affirmed, that " the area of a circle is equal to that of a triangle having the circumference for its base, and the radius for its altitude ;" would it not be an obvious... | |
 | Thomas Keith - 1817 - 306 ページ
...hence the circle is always limited between these polygons. The area of a circle is equal to that of u triangle, whose base is equal to the circumference, and perpendicular equal to tha radius. Circles, like other similar plane figures, are in proportion to one another, as the squares... | |
 | John Mason Good - 1819 - 694 ページ
...number«! the »ides of these it greater ; the circle being always limited between the two polygons. 3. The area of a circle is equal to that of a triangle...circumference, and perpendicular equal to the radius. A nd therefore the area of the circle is found by drawing half the circumference into half the diameter,... | |
 | William Hawney - 1820 - 336 ページ
...circumference of its inscribed polygon; hence the circle is always limited between these polygons. The area of a circle is equal to that of a triangle,...radius. Circles, like other similar plane figures, are in proportion to one another, as the squares of their diameters and the circumferences of circles,... | |
 | Dugald Stewart - 1821 - 348 ページ
...may be expressed by the formula a = a 1 Or, to take a case yet stronger, when it is affirmed, that " the area of a circle is equal to that of a triangle having the circumference for its base, and the radins for its altitude ;" would it • I do not think,... | |
 | 1824 - 492 ページ
...the Circle, he demonstrates the following theorem, which is of the greatest practical utility : That the area of a circle is equal to that of a triangle...circumference, and perpendicular equal to the radius. He also proved, That if the diameter of a circle be reckoned unity, the circumference will be between... | |
 | 1824 - 492 ページ
...the Circle, he demonstrates the following theorem, which is of the greatest practical utility : That the area of a circle is equal to that of a triangle whose lane is equal to the circumference, and perpendicular equal to the radius. He also proved, That if... | |
 | Dugald Stewart - 1829 - 418 ページ
...may be expressed by the formula a = a ? Or, to take a case yet stronger, when it is affirmed, that " the area of a circle is equal to that of a triangle having the circumference for its base, and the radius for its altitude ; " would it not be an obvious... | |
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Or, to take a case yet stronger, when it is affirmed, that " the area of a circle is equal to that of a triangle having the circumference for its base, and the radius for its altitude... 
