| T S. Taylor - 1880 - 152 ページ
...parallelogram. The enunciations of Euc. I. 4, I. 29, and I. 34. And Axioms 2a, 30, and 6. General Enunciation. Parallelograms on the same base, and between the same parallels, are equal to one another. Particular Enunciation (CASK I). Given — The parallelograms ABCD, DBCF, on the same... | |
| 1880 - 160 ページ
...angles ; and the three interior angles of every triangle are together equal to two right angles. (v.) Parallelograms on the same base, and between the same parallels, are equal to one another. (vi.) In any right angled triangle, the square which is described on the side subtending... | |
| Woolwich roy. military acad, Walter Ferrier Austin - 1880 - 190 ページ
...be greater than the third. How would the process fail if the last condition were not fulfilled ? 2. Parallelograms on the same base and between the same parallels are equal to each other. Show that if two triangles have two sides of the one equal to two sides of the other... | |
| Isaac Todhunter - 1880 - 426 ページ
...parallelogram ACDB into two equal parts. Wherefore, the opposite sides &c. QED PROPOSITION 35. THEOREM. Parallelograms on the same base, and between the same parallels, are equal to one another. Let the parallelograms ABCD, EBCF be on the same base BC, and between the sameparallels... | |
| Elizabethan club - 1880 - 156 ページ
...the other sides, and AD, £Cbe joined and intersect in E, show that the triangle AEB is isosceles. 2. Parallelograms on the same base, and between the same parallels are equal to each other. 3. If the sum of the squares described on two sides of a triangle is equal to the square... | |
| 1883 - 536 ページ
...and in it take any point P. Join P, A and P, B. The angle APB shall be greater than the angle ACB. 5. Parallelograms on the same base and between the same parallels are equal to one another. 6. Divide a given straight line into two parts, such that the difference of the squares... | |
| Arthur Sherburne Hardy - 1881 - 252 ページ
...the order of the factors, hence TV(a + /3)(a-/3)=2TVj8a, which is the proposition (Art. 41, 7). 13. Parallelograms on the same base and between the same parallels are equal. We have (Fig. 45) BE = BA + AE = BA + xBC. Operating with V . BC x V(BC . BE)=V(BC . BA), since VaBC2... | |
| John Gibson - 1881 - 64 ページ
...Propositions 33-40. 1. The opposite sides and angles of a parallelogram are equal to one another. 2. Parallelograms on the same base and between the same parallels are equal to one another. 3. Triangles on the same base and between the same parallels are equal. 4. Equal triangles... | |
| Isaac Sharpless - 1882 - 286 ページ
...of C, AC to BD, AB to CD, and the area of ABC to the area of BCD. N^ Proposition 33. ' Theorem. — Parallelograms on the same base and between the same parallels are equal. Let ABDC, EFDC be two parallels A EB p grams, on the same base CD and between ' the same parallels CD,... | |
| Great Britain. Education Department. Department of Science and Art - 1882 - 510 ページ
...how to draw a straight line through a given point, parallel to a given straight line. 11. Show that parallelograms on the same base and between the same parallels are equal. Show how to construct an isosceles triangle equal to a given triangle. '10.) 12. ABC is a triangle... | |
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