| Euclid - 1892 - 460 ページ
...produced to D, 20 that AD is equal to BA ; if DC is drawn, shew that BCD is a right angle. 2. The straight line joining the middle point of the hypotenuse of a right.angled triangle to the right angle is equal to half the hypotenuse. 3. From the extremities of the base of a triangle perpendiculars are... | |
| Queensland. Department of Public Instruction - 1892 - 508 ページ
...equal to the square on the other part. 10. Prove that the straight line joining the middle point 14 of the. hypotenuse of a right-angled triangle to the right angle is equal to half the hypotenuse. For Admission as Teacher of the Second Class. (Three hours allowed.)... | |
| Euclid, Henry Sinclair Hall, Frederick Haller Stevens - 1900 - 330 ページ
...produced to D, so that AD is equal to BA ; if DC is drawn, shew that BCD is a right angle. 2. The straight line joining the middle point of the hypotenuse of a right.angled triangle to the right angle is equal to half the hypotenuse. 3. From the extremities of the base of a triangle perpendiculars are... | |
| Euclid - 1904 - 488 ページ
...produced to D, so that AD is equal to BA ; if DC is drawn, shew that BCD is a right angle. 2. The straight line joining the middle point of the hypotenuse of a right-angled triangle to the right angle is f-qual to halfthe hypotenuse. 3. From the extremities of the base of a triangle perpendiculars are... | |
| Henry Sinclair Hall - 1908 - 286 ページ
...to D, so that AD is equal to BA ; if DC is drawn, shew that BCD is a right angle. 10. The straight line joining the middle point of the hypotenuse of a right-angled triangle to the right angle is equal to half the hypotenuse,. EXPERIMENTAL PROOF OF THEOREM 16. [A+B + C= 180°. ] In the A ABC, AD... | |
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