 | Alexander Hadden Hutchinson - 1861 - 128 ページ
...described upon the sides which contain the right angle. 2. If a straight line be divided into two equal and also into two unequal parts, the rectangle contained by the unequal parts together with the square cf the line between the points of section is equal to the square of half the line. VOLUNTARY PORTION.... | |
 | Euclides - 1861 - 464 ページ
...III. 47, I. Axs. 1, 2, 3, I. 36, 1. Parlms. upon eq. bases and between the same ||s are equal. 5, II. If a straight line be divided into two equal parts, and also into two uneq. parts, the rcct. contained by the nneq. parts, together with the square of the line between the... | |
 | Euclides - 1862 - 140 ページ
...the parallelograms about the diagonal of a square are likewise squares. PROPOSITION 5.— THEOREM. If a straight line be divided into two equal parts,...contained by the unequal parts, together with the square on the line between the points of section, ^s equal to the square on half the line. (References—... | |
 | Euclides - 1862 - 172 ページ
...that the parallelograms about the diameter of a square are likewise squares. PROP. V.— THEOREM. //' a straight line be divided into two equal parts, and also into two unequal parts ; then the rectangle contained by the unequal parts, together with the square of the line between the... | |
 | University of Oxford - 1863 - 316 ページ
...their other angles shall be equal, each to each, namely those to which the equal sides are opposite. 3. If a straight line be divided into two equal parts...contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. 4. Bisect a given... | |
 | Woolwich roy. military acad - 1864 - 588 ページ
...Chelsea be arranged, under the restriction that the tvco vowels e shall never stand together 1 10. If a straight line be divided into two equal parts,...contained by the unequal parts together with the square on the line between the points of section is equal to the square on half the line. Hence show that... | |
 | Euclides - 1864 - 262 ページ
...— 2am + m'. Hence by adding these equals, .'. (a + m)' + (a - m)* = 2az + 2m*. That is, If a number be divided into two equal parts, and also into two unequal parts, the sum of the squares of the two unequal parts is equal to twice the square of half the number itself,... | |
 | Euclides - 1864 - 448 ページ
...2am + at'. Hence by adding these equals, .-. (a + m)* + (o — m)' = 2aa + 2m'. That is, If a number be divided into two equal parts, and also into two unequal parts, the sum of the squares of the two unequal parts is equal to twice the square of half the number itself,... | |
 | Euclides - 1865 - 402 ページ
...by the parts. Cor. The parallelograms about the diameter of a square are likewise squares. Prop. 5. If a straight line be divided into two equal parts,...parts, together with the square of the line between the noinls of section, is equal to the square of half the line. Cor. The difference of the squares of two... | |
 | Robert Potts - 1865 - 528 ページ
...1am + m*, Hence by adding these equals, .'. (a + m)t + (a — m)« = 2o* + 2m«. That is, If a number be divided into two equal parts, and also into two unequal parts, the sum of the squares of the two unequal parts, is equal to twice the square of half the number itself,... | |
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If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line. 
