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書籍 To find the Area of a Triangle when the Three Sides are given. Rule. — From half... の書籍検索結果
" To find the Area of a Triangle when the Three Sides are given. Rule. — From half the sum of the three sides subtract each side separately. "
A Treatise on Surveying, Containing the Theory and Practice: To which is ... - 97 ページ
John Gummere 著 - 1814 - 346 ページ
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The artillerist's manual, and compendium of infantry exercise

Frederick Augustus Griffiths - 1859
...To find the area of a triangle, whose three sides are given. From half the sum of the three side?, subtract each side severally; multiply the half sum, and the three remainders together, and the square root of the product will be the area required. Example. — Required the area...

A handbook of practical gauging

Janes Boddely Keene - 1861
...feet ; what is its area in square yards ? Ans. 875 one-9th yds. When the Three Sides of a Triangle are given. RULE. — From half the sum of the three sides subtract each side separately ; then multiply the half sum and the three remainders together, and the square root of the...

Adams's Improved Arithmetic: Arithmetic, in which are Combined the Analytic ...

Daniel Adams - 1861 - 280 ページ
...the other ? Ans. 131 feet. To find the area of a triangle when the length of each side is given, — From half the sum of the three sides subtract each side severally ; then multiply the half sum and the three remainders continually together, and the square root of...

The young gardener's educator

William Keane (gardener.) - 1861
...field is by measuring the three sides separately. The rule for finding the content by the pen is : From half the sum of the three sides, subtract each side severally, then multiply the half sum and the three remainders together, and the square root of the last product...

The Practical Model Calculator, for the Engineer, Mechanic, Machinist ...

Oliver Byrne - 1863 - 588 ページ
...A " " 7J pa. = area required. To find the area of a triangle whose three sides only are given. — From half the sum of the three sides subtract each...severally. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required Required the area...

The Analysis of Written Arithmetic: Book Second, Designed for Public and ...

Stoddard A. Felter - 1864 - 394 ページ
...alt. area. 8ft. X 2 = 16 sq.ft. PROB. II. — The sides of a triangle being given to find the area. RULE. — From half the sum of the three sides subtract each side separately, then multiply the continued product of these remainders by half the sum of the sides, and...

Rudimentary treatise on mensuration and measuring

Thomas Baker (C.E.) - 1865
...has been made, and the work must be repeated. TO FIND THE AREA OF A TRIANGLE FROM THE THREE SIDES. RULE. — From half the sum of the three sides subtract each side severally and reserve the three remainders ; multiply the half sum continually by the three remainders, and the...

Orton's Lightning Calculator, and Accountant's Assistant: The Shortest ...

Hoy D. Orton - 1866 - 194 ページ
...problems are all very brief by canceling. To find Cite area of any triangle when the, three sides only are given. RULE. — From half the sum of the three sides subtract each side severally; multiply these three remainders and the said half sum, continually together • then the square root of the...

Elements of Plane and Solid Geometry: And of Plane and Spherical ...

Gerardus Beekman Docharty - 1867 - 283 ページ
...their included angle C=66° 30', to find the area. Aits. 11 acres, 2 roods, 11 perches. PROBLEM v. To find the area of a triangle when the three sides are given. From (prob. 4), Area of ABC= \ac sin. B. But, by (equation 51, Plane Trig.), 2 . sin. B=-Vs(s — a)(s—...

Elementary mensuration

Septimus Tebay - 1868 - 115 ページ
...120; at 126, 155; at 198, 140; at 240, 134; at 300, o. Ans. 1 r. 20-35 p. THE TRIANGLE CONTINUED. IX. TO find the area of a triangle when the three sides are given. From half the sum of the sides subtract each side separately; multiply the half sum and the three remainders...




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