 | Charles Davies - 1850 - 218 ページ
...each as there are sides of the polygon: hence, the sum of all the interior and exterior angles will be equal to twice as many right angles as the polygon has sides. But the sum of all the interior angles together with four right angles, is equal to twice as many right... | |
 | Charles Davies - 1886 - 340 ページ
...each as there are sides of the polygon : hence, the sum of all the interior and exterior angles will be equal to twice as many right angles as the polygon has sidesBut the sum of all the interior angles together with four right angles, is equal to twice as many... | |
 | Adrien Marie Legendre - 1852 - 436 ページ
...of each as there are sides of the polygon: hence the sum of all the interior and exterior angles, is equal to twice as many right angles as the polygon' has sides. Again, the sum of all the interior angles is equal to twice as many right angles as the figure has... | |
 | Euclides - 1853 - 334 ページ
...be proved. COB. 1. — All the interior angles of any polygon together with four right angles shall be equal to twice as many right angles as the polygon has sides. Let ABCDE be any polygon. Then all the angles at A, B, c, D, E together with four right angles shall... | |
 | Thomas Lund - 1854 - 520 ページ
...But the angles at 0 are equal to four right angles (30 Cor.); .'. all the angles of the polygon are equal to twice as many right angles as the polygon has sides, diminished by four right angles. COR. 1 . Hence, all the angles of a pentagon = 6 right angles ; hexagon... | |
 | Charles Davies - 1854 - 436 ページ
...figure has sides, less four right angles (P. 26). Hence, the interior angles plus four right angles, is equal to twice as many right angles as the polygon has sides, and consequently, equal to the sum of the interior angles plus the sum of the exterior angles. Taking... | |
 | George Roberts Perkins - 1856 - 460 ページ
...angle at D. THEOREM v. In any convex polygon, the sum of all the interior angles, taken together, is equal to twice as many right angles as the polygon has sides, wanting four right angles. Let ABCDFG be a convex polygon. Conceive the sides to be produced all in... | |
 | British and foreign school society - 1857 - 548 ページ
...alternate sides, also produced, the angles formed by these lines, together with eight right angles, are equal to twice as many right angles as the polygon has sides. 4. If two chords intersect in a circle, the difference of their squares is equal to the difference... | |
 | 1857 - 1266 ページ
...alternate sides, also produced, the angles formed by these lines, together with eight right angles are equal to twice as many right angles as the polygon has sides. 4. If two chords intersect in a circle, the difference of their squares is equal to the difference... | |
 | Elias Loomis - 1858 - 256 ページ
...equal to tw» right angles (Prop. XXVII.) ; therefore the sum of the angles of all the triangles, is equal to twice as many right angles as the polygon has sides. But the same angles are equal to the angles of the polygon, together with the angles at the point F,... | |
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... is equal to twice as many right angles as the polygon 
