 | Euclid, Isaac Todhunter - 1867 - 426 ページ
...meeting at F. Shew that the angle CFB is equal to half the sum of the angles EAC, EDB. 69. The straight line joining the middle point of the hypotenuse of a right-angled triangle to the right angle is equal to half the hypotenuse, 60. From the angle A of a triangle ABC a perpendicular is drawn to the... | |
 | Euclid, Isaac Todhunter - 1867 - 424 ページ
...meeting at F. Shew that the angle CFB is equal to half the sum of the angles EAC, EDB. 69. The straight line joining the middle point of the hypotenuse of a right-angled triangle to the right angle is equal to half the hypotenuse. 60. From the angle A of a triangle ABC a perpendicular is drawn to the... | |
 | Isaac Todhunter - 1880 - 426 ページ
...meeting at F. Shew that the angle CFB is equal to half the sum of the angles EAC, EDB. 59. The straight line joining the middle point of the hypotenuse of a right-angled triangle to the right angle is equal to half the hypotenusa 60. From the angle A of a triangle ABC a perpendicular is drawn to the... | |
 | 1883 - 536 ページ
...right angles. Explain the term corollary. Enunciate and prove corollaries to the above. 7. The straight line joining the middle point of the hypotenuse of a right-angled triangle to the right angle is equal to half the hypotenuse. 9. What axiom is understood as accepted for the early propositions of... | |
 | Education Ministry of - 1882 - 300 ページ
...triangles are equal. 3. Draw the figure required for Euclid, Book I., Prop. If perpendiculars bo drawn from the middle point of the hypotenuse of a right-angled triangle to the two sides, the square on the hypotenuse will be equal to four times the sum of the squares on the two... | |
 | Euclid, Isaac Todhunter - 1883 - 428 ページ
...meeting at F. Shew that the angle CFB is equal to half the sum of the angles EAC, EDB 69. The straight line joining the middle point of the hypotenuse of a right-angled triangle to the right angle is equal to half the hypotenusa 60. From the angle A of a triangle ABC a perpendicular is drawn to the... | |
 | Euclides - 1884 - 182 ページ
...right angles. If the figure wore a hexagon, the angles would be equal to four right 4. The straight line joining the middle point of the hypotenuse of a right-angled triangle to the right angle, is equal to half the hypotenuse. 5. Construct a right-angled triangle, having given the hypotenuse and... | |
 | Euclides - 1884 - 434 ページ
...of two sides of a triangle is || the third side, and = half of it. 2. Hence prove that the straight line joining the middle point of the hypotenuse of a right.angled triangle to the opposite vertex = half the hypotenuse. 3. The middle points of the sides of any quadrilateral are the... | |
 | John Casey - 1886 - 262 ページ
...extremities of the base ^ s of an isosceles A right lines are drawn _L to the sides, prove that the base L s of the A are each = half the L between the _Ls....a minimum. 32. If from the extremities A, B of the hase of a A ABC ±s AD, BE be drawn to the opposite sides, prove that AB" = AC . AE + BC . BD. 33.... | |
 | John Casey - 1888 - 279 ページ
...extremities of the hase £s of an isosceles A right lines are drawn _L to the sides, prove that the base L s of the A are each = half the L between the _Ls....hypotenuse. 31. The lines joining the feet of the Is of a A form an inscribed A whose perimeter is a minimum. 32. If from the extremities A, B of the... | |
| |
ABC a perpendicular is drawn to the opposite side, meeting it, produced if necessary, at D ; from the angle B a perpendicular is drawn to the opposite side, meeting it, produced if necessary, at E: shew that the straight lines which join... 
